THINK HIGH
Geometry
Level
1
In trapezoid ABCD with BC parallel to AD,let BC=1000 and AD=2008.let measure of angles A and D be 37 and 53 degrees,M and N be the midpoints of BC and AD,respectively.The length of MN is
504
400
500
404
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1 solution
Extend AB and CD to a point say L then <ALD=90 and A,M,N are collinear CM=LN=500 AND DN=LN=1004 MN=LN-LM=1004-500=504