It's obvious - isn't it?

If A and B are both equal to 0 then C=B however if they are any other integer then C does not equal B.

By the premises we find $2B =C$ This means $B = t, \quad C =2t$ is a solution for every $t \in \mathbb R$ . We also have that $B = C$ means $t = 2t$ this is true only when $t=0$ but indeed is a case that happens, so the answer is "sometimes".