∣ ∣ ∣ ∣ ∣ 3 sin x − 4 cos x + t + t 4 ∣ ∣ ∣ ∣ ∣
For all real t , let f ( t ) be the minimum of the above expression over x ∈ R .
Let ∫ 1 1 0 f ( t ) d t = 4 ( a + ln b ) for some rational a and b .
Find the value of a + 2 b .
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So if i well understand your solution, the problem is actually not correctly stated: t is the variable in the integral, and x is the variable from which we calculate the minimum. It should be written "let f(t) be the minimum value of the expression above", such that for t = 1 to 4 this is 0, for t = 4 to 10 this is (-5 + t + 4/t).
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Thanks. Those who answered 2 have been marked correct.
I have updated the problem to say:
- For all real
t
, let
f
(
t
)
be the minimum of the above expression over
x
∈
R
.
- Find
∫
f
(
t
)
d
t
(for consistency).
Does the problem look good now?
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3 sin x - 4 cos x takes values from -5 to 5 as t varies from 1 to 10 in such a way as to make the given expression a minimum. For t = 1 to 4 the expression is 0. For t = 4 to 10 integrate using the value of 3 sin x - 4 cos x = -5, to get a=3 and b = 2.5. Answer=8