Think simple

Algebra Level 3

If 2 < y < 3 -2 < y < 3 , then which of the following is true:

9 < ( y 2 ) 2 < 16 9 < (y-2)^2 < 16 0 ( y 2 ) 2 < 16 0 \leq (y-2)^2 < 16 1 < ( y 2 ) 2 < 16 1 < (y-2)^2 < 16 0 < ( y 2 ) 2 < 16 0 < (y-2)^2 < 16

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Julia Zibordi
Dec 26, 2018

If y y is greater than -2 but smaller than 3, then y y can be -1, 0, 1 or 2. If you try each one of these possibilities in ( y 2 ) 2 (y-2)^{2} , you'll see that ( 1 2 ) 2 (-1-2)^{2} = 9, ( 0 2 ) 2 = 4 (0-2)^{2} = 4 , ( 1 2 ) 2 = 1 (1-2)^{2} = 1 and ( 2 2 ) 2 (2-2)^{2} = 0. So the only possible answer is the third option. I'm sorry for any typos, I really hope I could help you understand this problem.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...