Think simpler!
If you randomly select four points on a sphere and create a tetrahedron by connecting the points, what is the probability that the tetrahedron contains the sphere's center point?
Note: Please answer the question as a simplified fraction with the numerator and denominator put together
For example: 6/8 = 3/4 =34 and NOT 6/8 = 68 and NOT 43
The answer is 18.
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