Think you are genius?

We don't need to prepare any equation. Just divide 102 by 3, then we will get 34 . That's the middle no. So the largest no. is 35.

x+x+1+x+2=102 3x+3=102 3x=102-3 3x=99 x=99/3 x=33 33+1=34 33+2=35

yup.. just like Prasad said.... it's very easy, just divide the number by 3.. and there you can find the middle number. before the middle no. is the lowest integer and after the middle no. is the largest integer.

let numbers be

x,x+1,x+2 and sum is 102 given

3*x=99

x=33

so 33,34,35.are the numbers and

35 is the largest

"The sum of three consecutive integers is $102$ " means: $\underbrace{(x-1)+x+(x+1)}_{\text{three consecutive integers}}=102.$ By solving for $x$ we get: $x=\dfrac{102}3=34$ which is the middle term, thus the largest integer in this case is $35$ .

x+x+1+x+2=102 implies, 3x+3 = 102 implies, 3x=99 implies, x=33. The largest integer is x+2 = 33+2=35

102/3= 34 it is middle integer , then ans. is 35

consecutive numbers ,there are three consecutive numbers so n+n+n=102. 3n=102 n=102 divided by3. n=34 now we know one number so you just have find the other 2 numbers and they are: 33and35.

x+x+1+x+2=102 3x+3=102 3x=102-3 3x=99 x=99/3 x=33 33+1=34 33+2=35

Let one integer be x. So the other 2 are x+1, x+2

Acc. to ques.

x+x+1+x+2 = 102

3x + 3 = 102

3x = 99

x = 33, x+1 = 34, x+2 = 35