Third Degree Equation
Algebra
Level
1
Find the "x" values that satisfies te expression:
-4, 4 or 12
3, -2 or 4
-3, 3 or 2
-2, 2 or 3
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1 solution
x 3 − 3 x 2 = 4 x − 1 2 x 2 ( x − 3 ) = 4 ( x − 3 ) ( x 2 − 4 ) ( x − 3 ) = 0 ( x + 2 ) ( x − 2 ) ( x − 3 ) = 0
x + 2 = 0 ⇒ x = − 2 x − 2 = 0 ⇒ x = 2 x − 3 = 0 ⇒ x = 3