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What is the smallest positive integer expressible as the sum of the cubes of two different integers in two different ways?

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The answer is 91.

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2 solutions

Anik Mandal
Feb 18, 2015

1729 \large{\boxed{1729}} is the smallest number expressible as the sum of the cubes of two positive \textbf{positive} integers in two different ways.

But since in the question it has been asked with reference to integers \textbf{integers} ,the least number in that case is 91 = 6 3 + ( 5 ) 3 = 4 3 + 3 3 \large 91=6^{3}+(-5)^3=4^{3}+3^{3}

If you allow for negative numbers, then you have to allow for a representation like 0 = 1 3 + ( 1 ) 3 = 2 3 + ( 2 ) 3 0 = 1^3 + (-1)^3 = 2^3 + (-2)^3 .

Jon Haussmann - 6 years, 3 months ago

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I have edited the question,sir.

Anik Mandal - 6 years, 3 months ago

I got the question right but can you please clarify that the number is positive. I tried 0 originally.

Sharky Kesa - 6 years, 3 months ago

Very nice question!!!!! Keep it up man!!!!!

Gagan Raj - 6 years, 3 months ago

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Thanks for your compliment!!

Anik Mandal - 6 years, 3 months ago
Ramiel To-ong
Jun 5, 2015

same solution

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