This is easier than it looks

In the alphabet, suppose we assign a value to all the alphabets such that A+B=C

B+C=D
C+D=E
and so on

And let A=D=333

find the value of M


The answer is 29637.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Daksh Shami
Mar 27, 2015

In the alphabet, suppose we assign a value to all the alphabets such that A+B=C B+C=D
C+D=E
and so on
now let A=D=1
1+B=C
B+C=1
so B=1-C
putting this in 1st eq., we get
1+1-C=C
2=2C
C=1
now A+B=C
1+B=1
B=0
so the series will become a fibonacci series from C to Z
Now to convert this into the desired series, we multiply each term by 333 hence when earlier M's value would be 89, now it would be 89 X 333 = 29637


0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...