This Is Geometry, Isn't It?

If the number of quadrilaterals in an n × n n\times n regular grid is x x , and the number of quadrilaterals in an n × n n\times n slope grid is y y , then what can you conclude about x x and y y ?

Clarification:

  • A quadrilateral is a polygon that has 4 sides.

This is one part of Quadrilatorics .
x < 2 y x<2y x > 2 y x>2y x = 2 y x=2y Pancake Not enough information

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Laurent Shorts
Apr 4, 2016

x = n 2 ( n + 1 ) 2 4 x=\frac{n^2(n+1)^2}{4} and y = ( n 1 ) n ( n + 1 ) ( n + 2 ) 24 r e c t a n g l e s + ( n 1 ) n ( n + 1 ) 3 t r a p e z i u m s = ( n 1 ) n ( n + 1 ) ( n + 10 ) 24 y=\frac{(n-1)n(n+1)(n+2)}{24}\mathrm{ rectangles }+\frac{(n-1)n(n+1)}{3}\mathrm{ trapeziums }=\frac{(n-1)n(n+1)(n+10)}{24} .

y y is ( n 1 ) n ( n + 1 ) ( n + 10 ) 24 \frac{(n-1)n(n+1)(n+10)}{24} , not ( n 1 ) n ( n + 1 ) ( n + 2 ) 24 \frac{(n-1)n(n+1)(n+2)}{24} .

Kenneth Tan - 4 years, 4 months ago

You're right, I counted only the rectangles… There's a ( n 1 ) n ( n + 1 ) 3 \dfrac{(n-1)n(n+1)}{3} number of trapeziums to add to it.

Laurent Shorts - 4 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...