This is Mathness!

You are given 10 10 digits from 0 0 to 9 9 .A crazy set is a set whose elements are one or more numbers whose digits are taken from 0 0 to 9 9 ,each digit used once compulsorily(in the whole set).

[For example , S = { 12 , 34 , 56 , 70 , 8 , 9 } S =\{12,34,56,70,8,9\} is crazy set because it consists of all digits
0 9 0-9 and in the total set each digit is used once!! Similarly S = { 1234567 , 890 } S = \{1234567,890\} is also a crazy set.]

Find the number of crazy sets whose sum of elements is 100 .


The answer is 0.

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2 solutions

Eddie The Head
Mar 11, 2014

Clearly for the sum to be 100 we cannot have any 3 digit numbers.....and since each digit is used once only,the sum of the digits of all the numbers will be 1 + 2 + . . . + 9 = 45 1+2+...+9 = 45 ..Let the sum of the numbers in the tens digit be x x ..So the sum of the number of the unit's digit = 45 x 45 - x ...Hence the value of the total number = 10 x + 45 x = 45 + 9 x 10*x+45-x = 45+9x Clearly 100 is not of the form 45 + 9 x 45+9x ..Hence it is not possible.....

Since each number can appear once...so the sum can go up to 45...max...not 100...Hence 0 sets

Each digit appears once in the whole set....not each number we can have a set like \{12345678,90} ...Clearly the sum is 12345768 >> 45...

Eddie The Head - 7 years, 3 months ago

See the example cases I have given in the problem.....

Eddie The Head - 7 years, 3 months ago

The largest possible number is 99 (60+1+2+3+4+5+7+8+9=99)

Nanayaranaraknas Vahdam - 7 years, 2 months ago

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