This is Mean!

Probability Level pending

Let n > 1 n>1 be a positive integer.

Consider " n n " numbers such that their mean is " M M ".

If one of the " n n " numbers, let's say " a a ", is gone, the mean is now " N N ".

Calculate " M − N M-N " in terms of " M M ", " n n " and " a a ".

(a-M)/(n-1) Mn/a (M-a)/(n-1) (M-n+a)/(n-1)

Natanael Flores by Natanael Flores , 31, Mexico

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1 solution

Natanael Flores
Feb 21, 2016

If a 1 + ⋯ + a n − 1 + a n = M \frac{a_1+\cdots+a_{n-1}+a}{n}=M and a 1 + ⋯ + a n − 1 n − 1 = N \frac{a_1+\cdots+a_{n-1}}{n-1}=N

then

n M − a = a 1 + ⋯ + a n − 1 nM-a=a_1+\cdots+a_{n-1}

so

N = n M − a n − 1 N=\frac{nM-a}{n-1}

Then just calculate M − N M-N ....

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