If N is a 6 digit number where 'abcdef' are the digits of N arranged in order, and then find N
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a b c d e f = 7 6 × d e f a b c
7 × a b c d e f = 6 × d e f a b c
7 × ( 1 0 5 a + 1 0 4 b + 1 0 3 c + 1 0 2 d + 1 0 e + f ) = 6 × ( 1 0 5 d + 1 0 4 e + 1 0 3 f + 1 0 2 a + 1 0 b + c )
( 7 × 1 0 5 − 6 × 1 0 2 ) a + ( 7 × 1 0 4 − 6 × 1 0 ) b + ( 7 × 1 0 3 − 6 ) c = ( 6 × 1 0 5 − 7 × 1 0 2 ) d + ( 6 × 1 0 4 − 7 × 1 0 ) e + ( 6 × 1 0 3 − 7 ) f
1 0 2 × ( 7 0 0 0 − 6 ) a + 1 0 × ( 7 0 0 0 − 6 ) b + ( 7 0 0 0 − 6 ) c = 1 0 2 × ( 6 0 0 0 − 7 ) d + 1 0 × ( 6 0 0 0 − 7 ) e + ( 6 0 0 0 − 7 ) f
6 9 9 4 × ( 1 0 2 a + 1 0 b + c ) = 5 9 9 3 × ( 1 0 2 d + 1 0 e + f )
6 9 9 4 × ( a b c ) = 5 9 9 3 × ( d e f )
5 3 8 ( a b c ) = 4 6 1 ( d e f )
As 538 and 461 don't have common factors
a b c = 4 6 1 a n d d e f = 5 3 8
N = a b c d e f = 4 6 1 5 3 8