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Geometry Level pending

Triangle $ABC$ has side lengths $AB=1617$ , $BC=1120$ , and $AC=1967$ . Point $D$ is constructed on the opposite side of line $AC$ as point $B$ such that $AD=1246$ and $CD=1071$ . Compute the distance from $B$ to the midpoint of segment $AD$ .

The answer is 728.

1 solution

Ferdinand Halim Santoso
May 22, 2016

We know, Triangle ABC is a right angle triangle. Then make point $E$ such that $EC$ is perpendicular to $BC$ and $EC=DC$ With Phytagoras Theorem, We know that $EA=DA$ Because $EA=DA$ and $EC=DC$ , So $E$ and $D$ are the same point So, the distance between $B$ and the midpoint of $AD$ = 728 We can calculate this with line equation

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The answer is 728.

1 solution

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