This is why Spiderman stretches every morning

In the movie Spiderman 2 , there's a famous minute long scene where Spiderman stops a train. If the initial speed of a five-car, out of control subway train was around the top speed of the NYC subway (27 m/s), and Spiderman stopped the train in exactly one minute, then what is the magnitude of the force in Newtons that Spiderman exerted on the train as he stopped it?

Details and assumptions

  • A standard New York City subway car full of terrified passengers has a mass of roughly 40,000 kg.
  • You may assume the acceleration was constant and any other forces are negligible.


The answer is 90000.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

David Mattingly Staff
May 13, 2014

Spiderman stops the train from an initial speed of 27 m/s in one minute, so the acceleration is a = ( 0 27 ) / 60 = 0.45 m/s 2 a=(0-27)/60=-0.45~\mbox{m/s}^2 . The force Spiderman exerted is then given by Newton's 2nd law, F = m a \vec{F}=m\vec{a} . The mass of 5 cars is 5 × 40 , 000 = 200 , 000 kg 5 \times 40,000=200,000~\mbox{kg} , and so the magnitude of the force Spiderman exerted is F = 200 , 000 × 0.45 = 90 , 000 F=|200,000 \times -0.45|=90,000 Newtons.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...