This one is Easy!

Algebra Level 3

0 z 0 \large \color{#D61F06}{0}^{\color{magenta}{z}} \not = \color{#D61F06}{0}

For what real value of z z can satisfy the above equation?

No real value can satisfy the equation . 0 1

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Hung Woei Neoh
Apr 14, 2016

Now, for any value of z > 0 z>0

We get 0 z = 0 0^z = 0

You can try it with a few values of z z

z = 1 0 z = 0 1 = 0 z = 2 0 z = 0 2 = 0 × 0 = 0 z = 3 0 z = 0 3 = 0 × 0 × 0 = 0 z = 1\implies 0^z = 0^1 = 0\\z = 2\implies 0^z = 0^2 = 0 \times 0 = 0\\z = 3\implies 0^z = 0^3 = 0 \times 0 \times 0 = 0

On the other hand, for any value of z < 0 z<0 , the expression 0 z 0^z is undefined, because

z < 0 0 z = 1 0 z = 1 0 = Undefined z < 0 \implies 0^z = \dfrac{1}{0^{-z}} = \dfrac{1}{0} = \text{Undefined}

z = 0 z = 0 is a special case

Mathematicians claim that 0 0 = 1 0^0=1

Read more about the value of 0 0 0^0 in this article

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...