This Question Should Have Been Posted 3 Years Ago

Let j = ( 2011 0 ) 3 0 + ( 2011 1 ) 3 1 + ( 2011 2 ) 3 2 + + ( 2011 1005 ) 3 1005 . j= \dbinom{2011}{0} 3^0 + \dbinom{2011}{1} 3^1 + \dbinom{2011}{2} 3^2 + \cdots + \dbinom{2011}{1005} 3^{1005}. Find the remainder when 2 2011 j 2^{2011}-j is divided by 201 1 2 . 2011^2.

Details and assumptions

  • This problem is not original.

  • You might use the fact that 2011 2011 is prime.


The answer is 1.

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