Mind-blowing Sequence.

Algebra Level 4

1 503 , 4 524 , 9 581 , 16 692 , 25 875 . . . . . . . \frac{1}{503},\frac{4}{524},\frac{9}{581},\frac{16}{692},\frac{25}{875}.......

Find the largest term of the above sequence ?


You can try my other Sequences And Series problems by clicking here : Part II and here : Part I.
4 524 \frac{4}{524} 16 692 \frac{16}{692} 49 1529 \frac{49}{1529} 49 1234 \frac{49}{1234}

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1 solution

U Z
Oct 1, 2014

its an calculas based problem

T n \huge{T_{n}} = n 2 500 + 3 n 3 \huge{\frac{n^{2}}{500 + 3n^{3}}}

then by differentiating and then keeping it to 0

we get 49 1529 \huge{\frac{49}{1529}}

Finding the General term of this sequence is quite interesting !!!

Sandeep Bhardwaj - 6 years, 8 months ago

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sir what was your method

U Z - 6 years, 8 months ago

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Same as yours. Just a little deep observation of the terms given. :)

Sandeep Bhardwaj - 6 years, 8 months ago

Good solution Megh

Sanjana Nedunchezian - 6 years, 8 months ago

But If we differentiate it and equal it to 0 0 we get maxima as 1 15. 3 2 3 \dfrac{1}{15.3^\dfrac{2}{3}}

Mehul Chaturvedi - 6 years, 5 months ago

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Well n has to be an integer and the practical maxima would be either 6 or 7

Soham Dibyachintan - 5 years, 11 months ago

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