This trip is too long.!
In a square shaped fixed compartment of side length
, a particle is projected with speed
from point A making
from horizontal as shown in the figure. Trip time is defined as time of journey of the particle from Wall 1 colliding with Wall 2, Wall 3, Wall,4 and returning to Wall 1 again. What is the trip number of trip whose trip time is 2 days if the given trip is trip number 1?
A is mid point of that side.
Coefficient of restitution = 0.5 Assume gravity free environment.
This problem is originally part of set Mechanics problems by Abhishek Sharma .
Try more problems here .
The answer is 5.
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1 solution
First of all consider the point A at upper corner of square on WALL 1. Then consider motion of particle in one direction either in left-right direction or in up-down direction.Speed will then become 1m/s(by taking the component).Then calculate time period for nth cycle and equate it to given time period. after solving you may get this [4^(n-1)] (3) (225)=(2) (24) (60)(60)