Next year polynomial

Algebra Level 3

P ( x ) P(x) is a 2018-degree monic polynomial such that P ( x ) = 2018 P(x)=2018 for x = 1 , 2 , 3 , . . . , 2017 x=1,2,3,...,2017 and P ( 2018 ) = 0 P(2018)=0 . What is the value of P ( 2018 + 2018 2017 ! ) ? \large P\left(2018+\frac{2018}{2017!}\right)?


The answer is 2018.

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1 solution

Akeyla Naufal
Dec 14, 2017

Let Q ( x ) = P ( x ) 2018 Q(x)=P(x)-2018 , then Q ( x ) Q(x) is a 2018-degree monic polynomial with 1 , 2 , 3 , . . . , 2017 1,2,3,...,2017 as its roots.
So , Q ( x ) = ( x 1 ) ( x 2 ) ( x 3 ) . . . ( x 2017 ) ( x k ) Q(x)=(x-1)(x-2)(x-3)...(x-2017)(x-k) , for a constant k k .
Substitute x = 2018 x=2018 , we get 2018 = 2017.2016.2015.....1. ( 2018 k ) -2018=2017.2016.2015.....1.(2018-k) , where we get k = 2018 + 2018 2017 ! k=2018+\frac{2018}{2017!}
Therefore , P ( 2018 + 2018 2017 ! ) = Q ( 2018 + 2018 2017 ! ) + 2018 = 0 + 2018 = 2018 P(2018+\frac{2018}{2017!})=Q(2018+\frac{2018}{2017!})+2018=0+2018=2018


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