Thorium-234 Decay: Positron & Alpha

Chemistry Level 2

90 234 T h + + 1 0 e → X X → 2 4 H e + Y _{90}^{234}Th + _{+1}^{\space 0}e \rightarrow X \\ X \rightarrow _2^4He + Y Thorium-234 \text{Thorium-234} undergoes positron absorption to form atom X \text{X} , which then undergoes α \alpha decay to form an alpha particle and atom Y \text{Y} . Determine the identity of Y \text{Y} and give your answer as the mass number \text{mass number} minus the atomic number \text{atomic number} .

David's Organic Chemistry Set

David's Physical Chemistry Set


The answer is 141.

David Hontz by David Hontz , 26, USA

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1 solution

David Hontz
Jul 1, 2016

90 234 T h + + 1 0 e → 90 + 1 234 + 0 X = 91 234 P a 91 234 P a → 2 4 H e + 91 − 2 234 − 4 Y ⇒ Y = 89 230 A c Answer = 230 − 89 = 141 _{90}^{234}Th + _{+1}^0e \rightarrow _{90+1}^{234+0}X = _{91}^{234}Pa \\ _{91}^{234}Pa \rightarrow _2^4He + _{91-2}^{234-4}Y \Rightarrow Y = _{89}^{230}Ac \\ \text{Answer} = 230-89 = \boxed{141}

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