Those Lucky Ducks

February 29 comes once in 4 years. Each Year consists of 365 days. Since there are $(365 \times 4) + 1$ days in 4 years (including leap year day)

i.e $\text{1461 days}$

Since the event comes once in 1461 days the proportion of people born on that day is:

$\dfrac{1}{1461}$ .

In this question basically probability has been asked of being born on 29th febuary.Since probability is given by

Possible outcomes/total no. Of outcomes

Total no.of outcomes in this case would be total no. Of days in 4 years that would be (365×3)+366, (366 because there would be one day extra on leap year) and possible outcomes is 1 i.e 29th febuary

Therefore probability =1/(365×3)+366

=1/1461

leap year comes after every 4 years.

so, it will be 1/(365 x 4 +1)

           =1/1461

The Gregorian calendar has February 29 occurring once every four years, meaning that we have 3 standard years of 365 days, and one leap year of 366.

$3\times365 + 366 = 1461$ , the question makes a lot of assumptions, but assuming that each day is as likely as every other, then it should be the reciprocal.

Giving us the solution: $\dfrac{1}{1461}$

Leap day is $1$ day in $four$ $years$ , so $1$ out of $(3)(365)+366=1461$ or $\frac{1}{1461}$

we know that 29 feb come after every 4 year..so we just have to see after how many days 29 feb came again so 365*4=1460 days and one is 29th feb so ttoal 1461 days after 29 feb come back..so ans is 1/1461