Three - Digit Numbers

How many three-digit numbers can be formed with the following conditions:

a. all digits are different
b. all digits are arranged in decreasing order


The answer is 120.

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1 solution

Any combination of 3 distinct digits chosen from 0 , 1 , . . . . , 9 0, 1, ...., 9 can be arranged in decreasing order in precisely one way, so the desired answer is ( 10 3 ) = 120 \dbinom{10}{3} = \boxed{120} .

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