Three Heads

7 32 \frac{7}{32} 5 32 \frac{5}{32} 1 4 \frac{1}{4} 9 32 \frac{9}{32}

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3 solutions

Ryan Redz
Jun 25, 2014

8C3/2^8 = 56/256 = 7/32

Tanya Gupta
Mar 9, 2014

8C3 to get 3 heads...out of total possible combinations of 2^8...on dividing we get 7/32!!!

Rishabh Nishad
Mar 4, 2014

The Binomial distribution has the probability function P(x=r)= nCr p^r (1-p)^(n-r) r=0,1,2,.....,n where nCr = n! / r! (n-r)! 1) n=8 (number of tosses) p=1/2 (probability of heads in a single toss) r= 3 P(r=3) = 8C3 (1/2)^3 (1/2)^5 = 0.218750

I converted the options in decimals.

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