Three numbers

There are three numbers on the board ( a , b , c a, b, c ).

Step: Delete one of the numbers. If N N equals to the sum of the two other numbers, then write down N 1 N-1 .

You can repeat the step above any number of times. Imagine that sometime there are three numbers on the board: 17 , 1983 , 1999 17,1983,1999 .

Which of the following sentences is/are true?

A : It is possible, that the original three numbers are ( a , b , c ) = ( 2 , 2 , 2 ) . (a,b,c)=(2,2,2).

B : It is possible, that the original three numbers are ( a , b , c ) = ( 3 , 3 , 3 ) . (a,b,c)=(3,3,3).

Neither A nor B Only B Only A Both of A and B

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Áron Bán-Szabó
Jul 26, 2017

Note that 1999 = 17 + 1983 1 1999=17+1983-1 . We will show that from after any step the sum of the two smallest numbers is 1 1 bigger, than the biggest number.

Suppose that for the ( a , b , c a, b, c ) numbers c = a + b 1 c=a+b-1 . The previous three numbers are ( a , b , x a, b, x ). Between these numbers the b b is the largest. So b = a + x 1 x = b a + 1 b=a+x-1\Leftrightarrow x=b-a+1 .

( 17 , 1999 , 1983 ) ( 17 , 1967 , 1983 ) ( 17 , 1967 , 1951 ) ( 17 , 15 , 31 ) ( 17 , 15 , 3 ) ( 13 , 15 , 3 ) ( 5 , 7 , 3 ) ( 5 , 3 , 3 ) (17,1999,1983)\Rightarrow (17,1967,1983)\Rightarrow (17,1967,1951)\Rightarrow \dots \Rightarrow (17,15,31)\Rightarrow (17,15,3)\Rightarrow (13,15,3)\Rightarrow \dots \Rightarrow (5,7,3)\Rightarrow (5,3,3)

We can get the ( 5 , 3 , 3 5,3,3 ) numbers from the ( 3 , 3 , 3 3,3,3 ) numbers, but we can't get it from the ( 2 , 2 , 2 2,2,2 ) numbers.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...