Three twin primes

We define a twin prime as a pair of prime numbers whose absolute difference is precisely 2.

Let p , q p,q and r r be odd prime numbers such that p , q p,q are twin primes and r r is a twin prime with some prime.

Given that p 2 + q 2 = r \dfrac{p^2+q}2 = r and p < r p < q < r < p 2 p<r-p< q < r < p^2 , find the product p q r pqr .


The answer is 105.

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2 solutions

Kushal Bose
Sep 24, 2016

As p p and q q are twin primes and p < q p<q .It can be concluded that q = p + 2 q=p+2 .

There exist only one integer between p , q p,q .So r p = q 1 = p + 1 = > r = 2 p + 1 r-p=q-1=p+1 \\ =>r=2 p+1

Putting all primes in terms of p p we get:

p 2 + p + 2 = 2 ( 2 p + 1 ) = > p 2 3 p = 0 = > p = 3 p^2+p+2=2 (2 p+1) \\ =>p^2-3 p=0 \\ => p=3 .

Then q = 5 , r = 7 q=5,r=7

Sswag SSwagf
Sep 24, 2016

We can develop all the statements to get

r = p + 4 r=p+4

q = p + 2 q=p+2

( r p ) = p + 1 (r-p)=p+1

( p + 4 ) p = p + 1 (p+4)-p=p+1

p = 3 p=3

so we have primes with the fllowing difference

3 , ( 3 + 2 ) , ( 3 + 4 ) 3, (3+2), (3+4)

p q r = 3.5.7 = 105 pqr=3.5.7=105

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