Throwing balls

In quick succession, a large number of balls are thrown vertically up in such a way that the next ball is thrown up when the previous ball reaches the maximum height.

If the maximum height is 5 m 5 \text{ m} , then find the number of balls thrown up per second.

4 2 none of these 1

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1 solution

Jus Jaisinghani
Jul 11, 2016

First one ball is thrown, the moment it reaches the maximum height the second ball is thrown lets Find the time taken to reach at the maximum height

  • v 2 = u 2 + 2 a s v^2=u^2+2as
  • u = 2 10 5 ( v = 0 ) u=\sqrt{2 \cdot 10 \cdot 5 } \dots(v=0)
  • u=10
  • v = u + a t v=u+at
  • t=1 s
  • Thus in one second 2 balls were thrown , the ans is 2 \boxed{2}

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