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Classical Mechanics Level 2

a pendulum in the clock with a mass 500 grams is swing with the highest point A (h) 20 cm from first position B. if The acceleration of gravity is − 9.8 m / s 2 -9.8 m/s^{2} , velocity of pendulum in B point is? velocity in m / s m/s


The answer is 1.98.

Andi M by Andi M , 24, Indonesia

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4 solutions

Andi M
Mar 8, 2014

using law of conservation of energy theory

E M A = E M B EM_A = EM_B

E p A + E k A = E p B + E k B Ep_A + Ek_A = Ep_B + Ek_B

m × g × h + 0 = 0 + 1 2 m × v 2 m\times g \times h + 0 = 0 + \frac{1}{2} m \times v^{2}

0.5 × 9.8 × 0.2 = 1 2 × 0.5 × v 2 0.5 \times 9.8 \times 0.2 = \frac{1}{2} \times 0.5 \times v^{2}

3.92 = v 2 3.92 = v^{2}

v = 1.979 = 1.98 m / s v = 1.979 = 1.98 m/s

3 Helpful 0 Interesting 0 Brilliant 0 Confused

oh my God

Lloyd Vincent Luardo - 7 years, 2 months ago

same way :)

Jung Hyun Ran - 7 years ago
Lira Zabin
Mar 9, 2014

KINETIC ENERGY IS EQUAL POTENTIAL ENERGY. THEN SOLVING THE EQUATIONS WE WILL GET VELOCITY

2 Helpful 0 Interesting 0 Brilliant 0 Confused

Speed at equilibrium:

v = 2 g h v=\sqrt{2gh}

v = 2 ∗ 9.8 ∗ 0.2 v=\sqrt{2*9.8*0.2}

v = 1.979... v=\boxed{1.979...}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Mgh=.5Mv² we know the g and h and we can calculate v....

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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