Tiger Woods thinks physics

The given momentum, $mv = 3~\textrm{kg m/s}$

We know, kinetic energy,

$\begin{aligned} E_k &= \frac{1}{2}mv^2 \\ &= \frac{1}{2}mv \times v \\ &= \frac {1}{2} \times 3~\textrm{kg m/s} \times v \\ &= \frac {3v}{2}~\textrm{J} \end{aligned}$

Hence, $\begin{aligned} E_k=\frac{3v}{2}~\textrm{J}=100~\textrm{J} \end{aligned}$

Therefore, $v=\left(100 \times \frac{2}{3}\right)~\textrm{m/s}=\frac{200}{3}~\textrm{m/s}$

Plugging in, we get...

$\begin{aligned} mv &= 3~\textrm{kg m/s} \\ \Longrightarrow m &= \frac{3~\textrm{kg m/s}}{v} \\ \Longrightarrow m &= \frac{3~\textrm{kg m/s}}{\frac{200}{3}~\textrm{m/s}} \\ \Longrightarrow m &= \left(\frac{3 \times 3}{200}\right)~\textrm{kg} \\ \therefore m &=\frac{9}{200}~\textrm{kg} \end{aligned}$

Converting to grams , we get...

$\frac{9}{200}~\textrm{kg}=\left(\frac{9 \times 10^3}{200}\right)~\textrm{grams}=45~\textrm{grams}$

Therefore, the required answer is $\fbox{45}$ !

We now that p^2=2m(K.e), Which means 3^2=2m100, As we have find the mass of the object in grams then we will multiply by 1000,

9000/200=m m=45

momentum= mv =3kg m/s (given) -Equation1

kinetic energy(Ek)= 1/2 mv^2 =100J (given)

Putting value of 'mv' in Equation1-

1/2v*3=100

v=200/3

Putting value of 'v' in Equation1-

m*200/3=3kg m/s

m=9/200kg

m=45g.

since, p=sqrt(2mEk), substituting the values,we get, sqrt(2m)=3/10, or,2m=9/100, or,m=0.045 kg=45g

Kinetic energy = 1/2 m v^2 = 100 J = 100 kg m^2/s^2

or, m*v^2 = 200 kg m^2/s^2 .... (1)

Momentum = mv = 3 kg m/s .... (2)

dividing (1) by (2) gives, v = 200/3 m/s

Replacing 'v' by 200/3 ms gives that, m = 0.045 kg = 45 grams

momentum=mass X velocity= 3000, KE=0.5 X mv^2 therefore,v=200/3 hence,mass(m)=9000/200= 45grams

K.E. = 1/2mv^2 = 100 J P = m.v = 3 kg m/s

P^2/K.E. = (mv)^2/(1/2)mv^2 = 9000/100 => 2m = 90 => m = 45 g