Tilted Parabolic Slide

A massive bead is positioned on a parabolic wire in the x y xy -plane with the following parametrization (all distances in meters): P = ( x , y ) = α v 1 + α 2 v 2 v 1 = ( 3 2 , 1 2 ) v 2 = ( 1 2 , 3 2 ) . \begin{aligned} \vec{P} = (x,y) &= \alpha\, \vec{v_1} + \alpha^2\, \vec{v_2} \\ \vec{v_1} &= \left(\frac{\sqrt{3}}{2},-\frac{1}{2} \right) \\ \vec{v_2} &= \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right). \end{aligned} There is an ambient gravitational acceleration of 10 m/s 2 10\text{ m/s}^2 in the y -y direction. The bead starts from rest at α = 1 \alpha = -1 , slides without losses along the wire, and leaves the wire at α = + 1 \alpha = +1 .

What is the bead's x x -coordinate when it crosses the x x -axis for the first time after leaving the wire?


The answer is 3.6514.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...