Time and work

Algebra Level 3

60 members can normally do a work in 40 days. However, after every 10 days, 5 members leave the group. How many days is needed to complete the work?

45 50 2100/2400 47.5

DineSh Vadlamudi by DineSh Vadlamudi , 25, India

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2 solutions

The job requires 60 ∗ 40 = 2400 60*40 = 2400 "worker-days" to complete. Since the n n th 10-day period involves 60 − 5 ( n − 1 ) 60 - 5(n - 1) workers, in the first 40 40 days there will be 10 ∗ ( 60 + 55 + 50 + 45 ) = 2100 10*(60 + 55 + 50 + 45) = 2100 worker-days completed, leaving 300 300 worker-days to be completed by 40 40 workers. This will then take up another 300 40 = 7.5 \dfrac{300}{40} = 7.5 days for a total of 47.5 \boxed{47.5} days to complete the job.

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Nice approach sir.

Abhay Tiwari - 5 years, 1 month ago
DineSh Vadlamudi
Jul 31, 2015

Have a try and then we go with the solution

0 Helpful 0 Interesting 0 Brilliant 0 Confused

This is not considered as the solution! Can you please post your method? @DineSh Vadlamudi

Sandeep Bhardwaj - 5 years, 9 months ago

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Work done by one person in one day is 1/2400. According to question... 10(60+55+50+45)w/2400 +40xw/2400=w 40xw/2400=300w/2400 4x=30 This implies x=7.5 days. Therefore total days required to complete is 47.5 days.

DineSh Vadlamudi - 5 years, 9 months ago

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