A IS TWICE AS GOOD A WORKMAN AS B AND TOGETHER THEY FINISH A PIECE OF WORK IN 18 DAYS. IN HOW MANY DAYS WILL A ALONE FINISH THE WORK?
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let the efficiency of b be x then its is given a;s efficiency is x/2 also they complete work in 18 days so equating one days work we get 2/x+1/x=1/18
3/x=1/18
x=3x18
x=54
x/2=27