Time Speed Distance problem 4 by Dhaval Furia
One can use three different transports which move at , , and kmph, respectively. To reach from A to B , Amal took each mode of transport of his total journey time, while Bimal took each mode of transport of the total distance. The percentage by which Bimal’s travel time exceeds Amal’s travel time is nearest to _____
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1 solution
Let T be Amal's total travel time (in hours). Then, his total distance traveled is:
10 (T/3) + 20 T/3 + 30 T/3 = 20 T km.
If T1 is the time Bimal spent traveling at 10 km/hr, we have:
(10 km/hr) (T1 hr) = 20 T/3 (km) or
T1 = (2*T/3)
The last equality follows from the fact that Bimal travels the same distance as Amal, and he is going at speed T1 for 1/3 of that distance.
Similarly, if T2 is the time Bimal travels at 20 km / hr and T3 is the time he travels at 30 km/hr, we see:
T2 = T/3 and
T3 = 2*T/9
Hence, the total travel time for Bimal is T1+T2+T3 = 11*T/9.
Hence, Bimal travels for 2*T/9 longer, which is 22.22% longer than T.