Time Speed Distance problem 7 by Dhaval Furia

Algebra Level pending

In a race of three horses, the first beat the second by 11 11 metres and the third by 90 90 metres. If the second beat the third by 80 80 metres, what was the length, in metres, of the racecourse?


The answer is 880.

Dhaval Furia by Dhaval Furia , 26, India

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1 solution

Let the required length be d d . Then according to the given conditions,

d − d ( d − 90 ) d − 11 = 80 d-\dfrac{d(d-90)}{d-11}=80

⟹ 79 d d − 11 = 80 ⟹ d = 880 \implies \dfrac {79d}{d-11}=80\implies d=\boxed {880} meters.

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