At the moment , an electron leaves one plate of a parallel plate capacitor with a negligible velocity. An accelerating voltage varying as , where is constant, is applied between the plates. The separation between the plates is . Let the time taken by the electron to reach the opposite plate be in microseconds.
What is
Details and Assumptions
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we know that V = Ed....here d=l therefore - E = V/d = bt/l... now force on electron = eE = ma where a is the acceleration..... hence a = ebt/ml .... writing a as (dv/dt) = ebt/ml and integrating we get v(velocity) = (eb(t^2))/ml again writing v as (dx/dt) = (eb(t^2))/ml and integrating..... we get X = (eb(t^3))/6ml putting X = l ..we get t = 1.505 sec