Timed swing

Assuming that this pendulum is indeed on Earth, what is the period of a simple pendulum 4ft long in seconds?


The answer is 2.2.

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2 solutions

Jason Fernandes
Feb 28, 2014

T = 2 π l g T=2\pi \sqrt { \cfrac { l }{ g } }
where, T is time period,
l is length of the pendulum,
g is gravitational acceleration.


Actually, you must mention that it is on earth then we can take g=pi^2, otherwise this question seems incomplete to me.

Kushagra Sahni - 7 years, 3 months ago

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Ok, I'm sorry. I will add that.

Robert Fritz - 7 years, 3 months ago

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Very good :)

Kushagra Sahni - 7 years, 3 months ago

Perfect!

Robert Fritz - 7 years, 2 months ago
Asif Iqbal
Mar 9, 2014

2.2

2.19 :)

Zāīd Mûghāl - 7 years, 2 months ago

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