Tired legs

Calculus Level 1

Frederick begins to walk a distance of 100 m . 100\text{ m}. But he is so tired that, in the first minute, he covers 50 m . 50\text{ m}. In the next minute, he covers half of the remaining distance, i.e. 25 m . 25\text{ m}. Again, in the next minute, he covers half of the remaining distance, which 12.5 m , 12.5\text{ m}, and so on.

Will Frederick be able to complete the 100 m ? 100\text{ m}?

Yes, between 30 and 60 minutes Yes, between the first and second hour Yes, within 15 minutes No

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

The distance Fredrick covers each minute is a geometric series given by:

50 , 25 , 12.5 , . . . 50, 25, 12.5,... \implies 50 × ( 1 , 1 2 , 1 4 , . . . ) 50\times (1, \frac{1}{2}, \frac{1}{4},...)

The sum of the series 1 , 1 2 , 1 4 , . . . 1, \frac{1}{2}, \frac{1}{4},... to n n terms is 2 ( 1 ( 1 2 n ) ) 2(1-(\frac{1}{2^n})) .

For Fredrick to cover 100 100 m m , the series sum should converge to 2 2 . But this happens only when n n\rightarrow\infty . Hence Fredrick can never cover the distance!

Actually 87.5 m 87.5m at third position...

Kelvin Hong - 3 years, 5 months ago
Raven Herd
Jan 17, 2018

Sum of an infinite gp

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...