An algebra problem by Aryan Gupta

Algebra Level pending

x 1 0 l o g ( n + 1 ) x 1 0 l o g ( n ) = x 1 0 l o g ( n 1 ) x^{10^{log (n+1)}}-x^{10^{log (n)}}=x^{10^{log (n-1)}}

If x satisfies the above equation enter the largest value of x upto three decimal places


The answer is 1.618.

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1 solution

Aryan Gupta
Feb 6, 2018

HINT: This can be simplified to x 2 x 1 = 0 x^2-x-1=0

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