Consider a titration of potassium dichromate solution with acidified Mohr's salt solution using diphenylamine as indicator. The number of moles of Mohr's salt required per mole of dichromate is...
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We know that for Mohr Salt, F e + 2 → F e + 3 so here change in Oxidation Number = 1
And for Potassium dichromate we have,
K X 2 C r X 2 O X 7 → C r + 3
So here change in O.N= 3 × 2 = 6 .
So the number of Mohr Salt is
n Mohr Salt × V × 1 = n K X 2 C r X 2 O X 7 × V × 6
⟹ n K X 2 C r X 2 O X 7 n Mohr Salt = 1 6
So Answer is 6