Titration...

Chemistry Level 2

Consider a titration of potassium dichromate solution with acidified Mohr's salt solution using diphenylamine as indicator. The number of moles of Mohr's salt required per mole of dichromate is...

2.75 7 6 4 5 3.5

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1 solution

Md Zuhair
Jan 3, 2018

We know that for Mohr Salt, F e + 2 F e + 3 \ce{Fe}^{+2} \rightarrow \ce{Fe}^{+3} so here change in Oxidation Number = 1 1

And for Potassium dichromate we have,

K X 2 C r X 2 O X 7 C r + 3 \ce{K2Cr2O7} \rightarrow \ce{Cr}^{+3}

So here change in O.N= 3 × 2 = 6 3 \times 2=6 .

So the number of Mohr Salt is

n Mohr Salt × V × 1 = n K X 2 C r X 2 O X 7 × V × 6 n_{\text{Mohr Salt}} \times V \times 1 = n_{\ce{K2Cr2O7}} \times V \times 6

n Mohr Salt n K X 2 C r X 2 O X 7 = 6 1 \implies \dfrac{n_{\text{Mohr Salt}}}{n_{\ce{K2Cr2O7}}} = \dfrac{6}{1}

So Answer is 6 6

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