Titration of H C l HCl and N a O H NaOH

Chemistry Level 1

The titration of 32.19 mL 32.19\text{ mL} of an HCl \text{HCl} solution of unknown concentration requires 24.59 mL 24.59\text{ mL} of a 0.100 M 0.100\text{ M} NaOH \text{NaOH} solution to reach the equivalence point. The molarity of the unknown HCl \text{HCl} solution is A . A. Find ⌊ 1000 A ⌋ \lfloor1000A\rfloor .


The answer is 76.

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Trevor B. by Trevor B. , 22, USA

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3 solutions

Trevor B.
Apr 30, 2014

Write out the equation: H C l ( a q ) + N a O H ( a q ) → H 2 O ( l ) + N a C l ( a q ) HCl\text{ }(aq)+NaOH\text{ }(aq)\rightarrow H_2O\text{ }(l)+NaCl\text{ }(aq)

Then solve for the molarity of H C l . HCl. 24.59 mL N a O H 1 × 0.100 mol N a O H 1000 mL N a O H × 1 mol H C l 1 mol N a O H × 1 0.02459 L H C l = 0.07639 M H C l \dfrac{24.59\text{ mL}\text{ }NaOH}{1}\times\dfrac{0.100\text{ mol}\text{ }NaOH}{1000\text{ mL}\text{ }NaOH}\times\dfrac{1\text{ mol}\text{ }HCl}{1\text{ mol}\text{ }NaOH}\times\dfrac{1}{0.02459\text{ L}\text{ }HCl}=0.07639\text{ M}\text{ }HCl

A = 0.07639 , A=0.07639, so ⌊ 1000 A ⌋ = 76 \lfloor1000A\rfloor=\boxed{76}

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Vishnudatt Gupta
Apr 30, 2014

we know that

m1v1=m2v2(as it is a neutralisation reaction)

by putting values we get

32.19 A=24.59 .1

A=76.390

1000*A=76.390

APPROX 76 IS THE ANSWER

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A is 76.390 and 1000A is also 76.390 ??? Please Correct it ...

Soutrik Bandyopadhyay - 7 years ago

We know that,

M1 V1 = M2 V2

=> 32.19 * A = 2.459 * 0.100

=> A =0.07639

=> floor(1000A) = 76

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