Titration

1 gram of commercial $\ce{AgNO3}$ is dissolved in 50 ml of water and then is treated with 50 ml of $\ce{KI}$ solution. The Silver Iodide thus precipitated is filtered. Excess of $\ce{KI}$ in the filtrate is treated with $\ce{KIO3}$ solution (M/10), in presence of 6M $\ce{HCl}$ till all Iodide ions are converted into $\ce{ICl}$ . According to the reaction $\ce{KIO3 +2KI +6HCl }$ gives $\ce{3ICl +3KCl +3H2O}$ .

It requires 50 ml of $\ce{KIO3}$ solution. 20ml of same stock solution of $\ce{KI}$ requires 30ml of M/10 $\ce{ KIO3}$ under similar condition.

Find the percentage of $\ce{ AgNO3}$ in the solution?