Titrations

$1 g$ sample of $\ce{AgNO3}$ is dissolved in $50$ $mL$ of water. It is titrated with $50$ $mL$ of $KI$ solution. The Silver Iodide precipitated is filtered off. Excess of $KI$ in filtrate is titrated with $M/10$ $\ce{KIO3}$ in presence of $6M$ $HCl$ till all $I^{-}$ is converted into $ICl$ . It requires $50$ $mL$ of $M/10$ $\ce{KIO3}$ solution. $20$ $mL$ of the same stock solution of $KI$ requires $30$ $mL$ of $M/10$ $\ce{KIO3}$ under similar conditions. The reaction is : $\ce{KIO3} + 2KI + 6HCl → 3ICl + 3KCl + 3\ce{H2O}$

The percentage of $\ce{AgNO3}$ in the sample is :