Is cell Z a mine?
Note : The number in each of the 4 open cells represents the number of hidden mines in the 8 cells around that number.
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If the question is instead "is there a configuration of mines consistent with this number pattern?" it becomes what is known as the Minesweeper Consistency Problem.
It's known to be a difficult problem to make a general algorithm for; in computer science jargon, it is NP-complete. Because of this, it is linked to something called the P vs. NP Problem, a problem considered significant enough that the Clay Mathematics Institute has offered a million-dollar prize for its solution.
One way to claim the prize would be to find an efficient algorithm to solve the Minesweeper Consistency Problem (in computer science jargon again, finding a polynomial-time algorithm).
Each number should have eight mine neighbours...
What is a mine? Please explain.
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Have you played minesweeper before??
Not having played minesweeper is your real problem here
A mine is a hidden bomb, usually underneath the surface of a superficial or some facade of some sort
Although I got it right, it should say that only one mine can be in a cell. Ed Gray
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That is a given for the game Minesweeper
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You should be aware that not everybody in the world was exposed to the game in their life, so this question could seem a bit irrational to them.
Oh yeah I got it
How did you work it out? Basically trial and error?
how ever if this applies to a real situation, it can be concluded that z has a mine. nobody would take the risk to step on that z, in reality or majority people would think that there is a mine. :-)
A red square means that a mine is placed on it. You can see that there is a way for Z to have a mine and not have a mine.
Its a mine
The exact same two I had as my examples.
I miscounted and tripped myself up. I hope I could have gotten it otherwise...
I feel that as the are numerous ways to arrange the bombs, so tbe above information is false. Also if it showed a hint or a start or a technique it would probably be solved.
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No, there are exactly 3 possible arrangements, one of which is symmetric to the seccond example @Zain Majumder has given, therefore, the above information is true.
On the other hand, I do agree that they could have given some more details about minesweeper rules, or at least provide us with a link.
If atleast one combination of mines can be found for which Z is a mine and Z is not a mine, we can conclude information is not enough.
Just try to find a arrangement where Z is not a mine ; because there are a lot of clearly obvious ways of Z being a mine.
The information is not sufficient enough beccause the no of bombs in 8 cells are arbitary so there are infinite ways of arranging the bombs....so there are cases whenre in bomb may be present on z or not
Answer is C: Probability of Z being a mine because of 6=6/8 Probability of Z being a mine because of 2=2/8 Probability of Z being a mine because of 4=4/8 Probability of Z being a mine because of 6=6/8 Total probability=36/324 Hence we can't be sure
It is possible to find a solution when all the conditions are satisfied but Z is not a mine at the same time we can also obtain a solution where all the conditions are satisfied but Z is a mine .
Trying a combination that doesn’t include Z as a mine shows that it’s possible for Z not be a mine, and since it’s obvious that Z can be a mine too, it means that there are not enough information
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