A river of 4 meters wide has a curve of 90 °. Is it possible to cross the river by making a bridge with only two planks 3.9 meters long each?
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Using one plank diagonally across the outside corner (forming an isosceles triangle), and the other perpendicular from the first plank to the inside corner, we can create a self-supporting bridge.
The distance we need to cover, from the outside corner to the inside corner, is 4 m 2 + 4 m 2 = 5 . 6 5 7 m
Measurements allow for a 0.05m overlap to be used to support the planks at each end.
Allowing 0 . 0 5 m for support at each end of the planks, the first diagonal plank will effectively achieve a distance of 2 3 . 8 m = 1 . 9 m from the outside corner (due to the symmetry of the isosceles triangle).
This leaves 5 . 6 5 7 m − 1 . 9 m = 3 . 7 5 7 m to cover with the remaining plank, which is certainly possible with a plank of 3 . 9 m , even with an allowance at either end of the plank for support.
If the planks had negligible width, they would have to be greater than 3 2 4 m 2 + 4 m 2 = 3 . 7 7 1 2 3 6 1 6 6 3 2 8 2 5 m in length to be able to form a self-supporting bridge.