To cross the river

Logic Level 1

A river of 4 meters wide has a curve of 90 °. Is it possible to cross the river by making a bridge with only two planks 3.9 meters long each?

Details and assumptions:

  • He has no nails, no hammers, nothing of the sort.
It's not possible It's possible

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1 solution

Jonathan Quarrie
Sep 10, 2017

Using one plank diagonally across the outside corner (forming an isosceles triangle), and the other perpendicular from the first plank to the inside corner, we can create a self-supporting bridge.

The distance we need to cover, from the outside corner to the inside corner, is 4 m 2 + 4 m 2 = 5.657 m \sqrt{4m^2 + 4m^2} = \color{#D61F06}5.657m

Measurements allow for a 0.05m overlap to be used to support the planks at each end. Measurements allow for a 0.05m overlap to be used to support the planks at each end.

Allowing 0.05 m 0.05m for support at each end of the planks, the first diagonal plank will effectively achieve a distance of 3.8 m 2 = 1.9 m \dfrac{\color{#3D99F6}3.8m}{2} = \color{#20A900}1.9m from the outside corner (due to the symmetry of the isosceles triangle).

This leaves 5.657 m 1.9 m = 3.757 m \color{#D61F06}5.657m \color{#333333}- \color{#20A900}1.9m \color{#333333}= \color{#E81990}3.757m to cover with the remaining plank, which is certainly possible with a plank of 3.9 m \color{#3D99F6}3.9m , even with an allowance at either end of the plank for support.

If the planks had negligible width, they would have to be greater than 2 3 4 m 2 + 4 m 2 = 3.77123616632825 m \dfrac{2}{3}\sqrt{4m^2 + 4m^2} = 3.77123616632825m in length to be able to form a self-supporting bridge.

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