To prove!!!
The equation of displacement of the above system connecting masses 1kg and 2kg with a rope is-
x=6t -6t where x is displacement and t is time .
Find the value of magnitude of acceleration of system(a) + magnitude of Tension in the rope(T) + magnitude of force acting(F)
Details and Assumptions
• F is the force acting on block having mass 1 kg .
• Refer to diagram for details of the directions of vectors
• The rope is ideal
• All surfaces are frictionless
My inspiration Aniket Sanghi
The answer is 72.
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1 solution
The acceleration of system(a)= d t ² d ² x =12m/s²
F o r c e a c t i n g ( F ) = m a s s o f s y s t e m × a c c e l e r a t i o n o f s y s t e m
= 3 × 1 2 = 3 6 N
As per F.B.D. of block having mass 2kg, T=2×12=24N
Hence, answer=72