All the 2-digit numbers from 19 to 93 are written consecutively to form the number N=19202122...919293. Find the largest power of 3 that divides N.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Now first we try to find it is divisible by 3. Its easy as we know that if the sum of the digits is divisible by 3 then the number is also divisible by 3. Noting that 1 occurs 9 times in the digits from 19 to 93, 2 occurs 18 times..etc, we find the sum to be 717. This is divisible by 3 (7+1+7=15) but not by 9. So highest power of 3 dividing N is 3.