Too many ones

Find the square of the number 111 , 111 , 111 111,111,111 .

Just to clarify: the number is one hundred eleven million, one hundred eleven thousand, one hundred eleven.


The answer is 12345678987654321.

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2 solutions

Discussions for this problem are now closed

Anna Anant
Jan 6, 2015

Repeated 1 is a special number that if multiply by itself will result in a number sequence from 1 to n (where n is the number of 1) and count down to 1.

E.g. 1111*1111 = 1234321 because there are four 1. But this rule only applies if the number of 1 is less than 10. So 111,111,111 squared is 123456789 and then count down to 1 12345678987654321

Chew-Seong Cheong
Dec 29, 2014

This can be solved by induction as follows.

1 1 2 = 121 11 1 2 = 12321 1 , 11 1 2 = 1234321 11 , 11 1 2 = 123454321 111 , 11 1 2 = 12345654321 1 , 111 , 11 1 2 = 1234567654321 11 , 111 , 11 1 2 = 123456787654321 111 , 111 , 11 1 2 = 12345678987654321 \begin {matrix} 11^2 & = & 121 \\ 111^2 & = & 12321 \\ 1,111^2 & = & 1234321 \\ 11,111^2 & = & 123454321 \\ 111,111^2 & = & 12345654321 \\ 1,111,111^2 & = & 1234567654321 \\ 11,111,111^2 & = & 123456787654321 \\ 111,111,111^2 & = & \boxed{12345678987654321} \end {matrix}

Moderator note:

Poor choice of phrasing. Your implication of "induction as follows" suggests that 1 , 111 , 111 , 11 1 2 = 12345678910987654321 1,111,111,111^2 = 12345678910987654321 , 11 , 111 , 111 , 11 1 2 = 123456789101110987654321 11,111,111,111^2 = 123456789101110987654321 , and so on. Which is clearly wrong. You should mention this pattern only works when the number is in the form 111 1 n 1 ’s \underbrace{111 \ldots 1}_{n \ 1\text{'s}} for n = 1 , 2 , 3 , , 9 n=1,2,3, \ldots , 9 only.

I was actually more concerned about typing the answer correctly than typing the correct answer lol :)

Wee Xian Bin - 6 years, 5 months ago

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