Too many 5's

quite easy,needn't to find whole number: $let\quad x\quad be\quad the\quad quotient\quad when\quad multiplied\quad by\quad 2003\quad gives\quad 55555555.....5555\\ don't\quad know\quad the\quad number\quad of\quad fives.\\ in\quad order\quad to\quad obtain\quad first\quad 5:\quad 3\quad should\quad be\quad multiplied\quad by\quad 5,\\ so\quad unit\quad digit\quad is\quad 5.\\ 3\times 5\quad is\quad 15\quad therefore\quad in\quad order\quad to\quad make\quad tens\quad digit\quad ten\quad we\quad need\quad to\quad add\quad 4\quad to\quad the\\ ten's\quad digit\quad or\quad find\quad the\quad number\quad when\quad multiplied\quad by\quad 3\quad gives\quad unit\quad digit\quad 4.the\\ number\quad is\quad 8\quad so\quad the\quad ten's\quad digit\quad is\quad 8.\\ now\quad the\quad hundred's\quad place,\quad since\quad 2\quad is\quad already\quad is\quad hundred's\quad digit\quad in\quad order\quad to\quad get\\ 5\quad need\quad to\quad add\quad 3\quad or\quad find\quad the\quad number\quad when\quad multiplied\quad by\quad 3\quad gives\quad unit\quad digit\quad 3,hence\\ the\quad number\quad is\quad 1\quad and\quad hence\quad answer\quad is\quad \boxed{185}$

Here's a python 3.0+ script to achieve the same:

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n=5555
while(True):
    if(n%2003==0):
        break
    n = n*10+5
print(n//2003%1000)