Monic quadratic polynomials and have the property that has zeros at and , and has zeros at and . What is the sum of the minimum values of and ?
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Since both P ( Q ( x ) ) and Q ( P ( x ) ) have four distinct real zeros, both P ( x ) and Q ( x ) must have two distinct real zeros. Hence, we can write P ( x ) = ( x − h 1 ) 2 − k 1 2 and Q ( x ) = ( x − h 2 ) 2 − k 2 2 .
The zeros of P ( x ) are h 1 ± k 1 , so the zeros of P ( Q ( x ) ) are the roots of Q ( x ) = h 1 ± k 1 . Since the function Q ( x ) = ( x − h 2 ) 2 − k 2 2 is symmetric around x = h 2 , the roots of Q ( x ) = h 1 + k 1 must be symmetric around x = h 2 , and the roots of Q ( x ) = h 1 − k 1 must also be symmetric around x = h 2 . The values − 2 3 , − 2 1 , − 1 7 , and − 1 5 are symmetric around − 1 9 , so h 2 = − 1 9 . Then Q ( x ) = ( x + 1 9 ) 2 − k 2 2 .
Since Q ( x ) is monic, Q ( x ) is decreasing on the interval ( − ∞ , − 1 9 ] and increasing on the interval [ − 1 9 , ∞ ) . Therefore, the roots of Q ( x ) = h 1 − k 1 are − 2 1 and − 1 7 , and the roots of Q ( x ) = h 1 + k 1 are − 2 3 and − 1 5 . Hence, Q ( − 1 7 ) = h 1 − k 1 and Q ( − 1 5 ) = h 1 + k 1 , so Q ( − 1 5 ) − Q ( − 1 7 ) = 2 k 1 . But Q ( − 1 5 ) − Q ( − 1 7 ) = [ ( − 1 5 + 1 9 ) 2 − k 2 2 ] − [ ( − 1 7 + 1 9 ) 2 − k 2 2 ] = 1 6 − 4 = 1 2 , so 2 k 1 = 1 2 , which means k 1 = 6 .
Similarly, the zeros of Q ( x ) are h 2 ± k 2 , so the zeros of Q ( P ( x ) ) are the roots of P ( x ) = h 2 ± k 2 . Since the function P ( x ) = ( x − h 1 ) 2 − k 1 2 is symmetric around x = h 1 , the roots of P ( x ) = h 2 + k 2 must be symmetric around x = h 1 , and the roots of P ( x ) = h 2 − k 2 must also be symmetric around x = h 1 . The values − 5 9 , − 5 7 , − 5 1 , and − 4 9 are symmetric around − 5 4 , so h 1 = − 5 4 . Then P ( x ) = ( x + 5 4 ) 2 − k 1 2 .
Since P ( x ) is monic, P ( x ) is decreasing on the interval ( − ∞ , − 5 4 ] and increasing on the interval [ − 5 4 , ∞ ) . Therefore, the roots of P ( x ) = h 2 − k 2 are − 5 7 and − 5 1 , and the roots of P ( x ) = h 2 + k 2 are − 5 9 and − 4 9 . Hence, P ( − 5 1 ) = h 2 − k 2 and P ( − 4 9 ) = h 2 + k 2 , so P ( − 4 9 ) − P ( − 5 1 ) = 2 k 2 . But P ( − 4 9 ) − P ( − 5 1 ) = [ ( − 4 9 + 5 4 ) 2 − k 1 2 ] − [ ( − 5 1 + 5 4 ) 2 − k 1 2 ] = 2 5 − 9 = 1 6 , so 2 k 2 = 1 6 , which means k 2 = 8 .
The minimum value of P ( x ) = ( x − h 1 ) 2 − k 1 2 is − k 1 2 , and the minimum value of Q ( x ) = ( x − h 2 ) 2 − k 2 2 is − k 2 2 , so the sum of their minimum values is − k 1 2 − k 2 2 = − 3 6 − 6 4 = − 1 0 0 .