Too Many Variables!

Classical Mechanics Level 5

The Density Of A Solid At Normal Pressure Is "P" . When The Solid Is Subjected To An Excess Pressure "J" , The

Density Of The Solid Changes To "Q" . If The Bulk Modulus Of The Solid Is "K" Then Calculate The Ratio Of Q/P .

Details And Assumptions

Ratio Of J And K (J/K) = 1/2

1 solution

Samarth Agarwal
Nov 24, 2015

K=- $\frac{V d(Pressure)}{dV}$

- $\frac{dV}{V}$ = $\frac{J}{K}$

V $\cdot$ Density=mass

Differentiating w.r.t. V

V $\cdot$ d(Density) + (Initial density) $\cdot$ dV=0

$\therefore$ - $\frac{dV}{V}$ =d(Density)/(Initial Density)

$\therefore$ $\frac{Q-P}{P}$ = $\frac{1}{2}$

$\implies$ 2Q=3P

$\implies$ Q/P=1.5

Perfect ! +1

Prakhar Bindal - 5 years, 6 months ago